4. (x - 2 = 1 X-2 =1 x = 1+2. X-2=-1 x= -1+2 x = ..... x = ....
1. 4. (x - 2 = 1 X-2 =1 x = 1+2. X-2=-1 x= -1+2 x = ..... x = ....
Jawaban:
(x-2=1
X-2=1
x=1+2
X-2=-1
X=-1+2
x=1
Jadi jawabannya adalah 1
semoga membantu
2. Hasil bagi dari pembagian suku banyak (x^6-1):(x²-1) adalah... a. (x^2+x+1) (x^2+x-1) b. (x^2+x+1) (x^2-x+1) c. (x^2+x+1) (x^2-x-1) d. (x^2-x+1) (x^2+x-1) e. (x^2+x-1) (x^2-x-1) beserta caranya ya..
Penjelasan dengan langkah-langkah:
dilampirkan pada gambar...
3. Mohon bantuannya x^6 - 1 / x^2 - 1 sama dengan...a. x^4-1b. (x^2+x+1)(x^2-x+1)c. (x^2+x+1)(x^2-x-1)d. (x^2+x-1)(x^2-x+1)e. x^4+x^2+1
Jawaban:
e. x^4+x^2+1
Penjelasan dengan langkah-langkah:
semoga benar
4. 1/2 x 1/2 x 1/2 x 1/2 x 1/2 =
1/2 pangkat 5=0.01325
kalo gk salah1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 1/32
5. X²(2× -1)- x(x²+×+1)+2(x²-x+1
Jawaban:
x³ - 3x + 2
Penjelasan dengan langkah-langkah:
X²(2× -1)- x(x²+×+1)+2(x²-x+1)
2x³ - x² - x³ - x² - x + 2x² -2x + 2
2x³ - x³ - x² - x² + 2x² - x -2x + 2 (dikelompokkan)
x³ - 2x² + 2x² - 3x + 2
x³ - 3x + 2
( karena -2x²+2x² = 0 maka tidak perlu di tulis)
6. 1. Lim x -> 1 x^2-1 / x^2+3x-2 2. Lim x -> -1 (x+1)(x-4)+2(x-1) / x^2+x-2
1) lim x>1 (x-1)(x+2)/ (x+1)(x+2)
=lim x>1 (x-1)/(x+2)
=(1-1)(1+2)
=0/3
=0
2) lim x-> -1 (x+1)(x-4)+2/(x+2)
=(-1+1)(-1-4)+2/(-1+2)
=(0)(-5)+2/(1)
=0+2/1
=2/1
=2
7. 1] Jika f(x) = 1/2(a^x + a^-x) dan g(x) = 1/2(a^x - a^-x), maka f(x) . f(y) + g(x) . g(y) sama dengan ? 2] Jika x^1/2 + x^-1/2 = 2, maka nilai dari x^2 + x^-2 adalah ? 3] Jika x^1/2 + x^-1/2 = 2, maka x^3/2 + x^-3/2 sama dengan ?
E|<sp0|\|en
1]
f(x) = 1/2 (a^x + a^-x)
g(x) = 1/2 (a^x - a^-x)
•
f(x) . f(y) + g(x) . g(y)
= (1/2)^(a^x + a^-x) . (1/2)^ (a^y + a^-y) + (1/2)^(a^x + a^-x) . (1/2)^ (a^y + a^-y)
= 2 . (2^-1)^((a^x + a^-x) + (a^y + a^-y))
= 2^(1 - a^x - a^-x - a^y - a^-y)
2]
→ (a + b)² = a² + b² + 2ab
•
x^1/2 + x^-1/2 = 2
(x^1/2 + x^-1/2)² = 2²
x + 1/x + 2 = 4
x + 1/x = 2
•
(x + 1/x)² = 2²
x² + 1/x² + 2 = 4
x^2 + x^-2 = 2 ✔
3]
x^1/2 + x^-1/2 = 2
•
(x + 1/x)(x² + 1/x²) = x³ + x + 1/x + 1/x³
x³ + 1/x³ = (x + 1/x)(x² + 1/x²) - (x + 1/x)
•
x³ + 1/x³
= (x + 1/x)(x² + 1/x²) - (x + 1/x)
= 2 × 2 - 2
= 2 ✔
8. Jika tan 5⁰ = x, tentukan nilai sin 50⁰ ...A.√2/2 ((x+1)/√(x^2-1))B.√2/2 ((x+1)/√(x^2+1))C.√2/2 ((x-1)/√(x^2+1))D.√2/3 ((x+1)/√(x^2+1))E.√2/3 ((x-1)/√(x^2+1))
Jawab:
B.√2/2 ((x+1)/√(x^2+1))
Penjelasan dengan langkah-langkah:
tan 5= x= x/1 » r = √(x²+1)
sin 5 = x/√(x²+1)
cos 5= 1/√(x²+1)
sin 50= sin (45+5)
= sin 45cos5 + cos 45sin 5
=√2/2 . 1/√(x²+1) + √2/2 . x/√(x²+1)
= √2 / 2√(x²+1) + x√2 / 2√(x²+1)
=( x√2 + √2) / 2√(x²+1)
= √2(x+1) / 2√(x²+1)
= √2/2 [ (x+1)/(x²+1) ]
9. Penyelesaian dari pertidaksamaan( X+ 2) (X+1) ≤ 0 adalah.....a. {−2 ≤ x ≤ −1}b.{−1 ≤ x ≤ 1 }c.{−2 ≤ x ≤ 1 }d.{ x ≤ −2 atau x ≥ 1}e.{x ≤ −1 atau x ≥ 2}
Jawaban:
jawabannya A
Penjelasan dengan langkah-langkah:
(x+2) (x+1) <= 0
x=-2 x=-1
{-2<= x <= -1}
10. 1/2 x 1/2 x 1/2 x 1/2 x 1/2=
2×2×2×2×2=36
maaf kalo salah
11. 1/2 x 1/2 x 1/2 x 1/2 ( 1 per 2 x 1 per 2 x ,1 per 2 x 1 per 2 ) nyatakan dalam bentuk bilangan berpangkat
Jawaban:
[tex]\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = { \frac{1}{2} }^{4}[/tex]
12. T (x) = R (x^2 +1) = (x^2 + 1) / x^2 , makaT (R(x))= [(R(x))^2 + 1] / (R(x))^2 =[[x/(x-1)]^2 +1] / [x/(x-1)]^2 = (2x^2 -2x + 1) / x^2Jika R(x) = x-1/x+1 dan T(x) = x^2+1/x(1-x), maka(R o T)(x) = ....
Jawaban:
1.garis sejajar
2.garis berpotongan
3.garis berimpit
1.garis sejajar
2.garis berpotongan
3.garis berimpit
13. 1.(2-x)<(x+1) = 2.(x²)>x+1 = 3.(2-x)≤x+1 =
Jawab:
1.dikuadratkan kanan kiri
x^2 -4x +4 = x^2 - 2x +1
-4x + 4 = -2x +1
2x = 3
x =3/2
untuk no 2 sama 3 pake foto ya
14. Tentukan solusi x dan tuliskan himpunan penyelesaiannya. 1. (x+ 1)^2 - (x - 1)^2 = x + 9 2. (3x - 1)(x + 1) = 3x^2 3. (x + 4) (x - 1) = (x + 2)(x - 3) 4. (X - 3)^2 + (x + 1)^2 = (x - 2)^2 + (x + 3)^2
1. [x^2 + 2x + 1] - [x^2 - 2x + 1] = x + 9
4x = x + 9
3x = 9
x = 3
15. Jika x^1/2 + x^-1/2 = 2 Maka x^2 +x^-2= ...?
Diketahui [tex]x^{\frac{1}{2}}+x^{-\frac{1}{2}}=2[/tex]
Kuadratkan kedua ruas,
=> [tex](x^{\frac{1}{2}}+x^{-\frac{1}{2}}-2)^{2}=0[/tex]
=> [tex](x^{\frac{1}{2}}+x^{-\frac{1}{2}}-2)(x^{\frac{1}{2}}+x^{-\frac{1}{2}}-2)=0[/tex]
=> [tex]x+1-2x^{\frac{1}{2}}+1+x^{-1}-2x^{-\frac{1}{2}}-2x^{\frac{1}{2}}-2x^{-\frac{1}{2}}+4=0[/tex]
=> [tex]x-4x^{\frac{1}{2}}+x^{-1}-4x^{-\frac{1}{2}}+6=0[/tex]
=> [tex]x+x^{-1}-4(x^{\frac{1}{2}}+x^{-\frac{1}{2}})=-6[/tex]
=> [tex]x+x^{-1}-8=-6[/tex]
=> [tex]x+x^{-1}=2[/tex]
Sekarang kuadratkan lagi,
=> [tex](x+x^{-1}-2)^{2}=0[/tex]
=> [tex](x+x^{-1}-2)(x+x^{-1}-2)=0[/tex]
=> [tex]x^{2}+1-2x+1+x^{-2}-2x^{-1}-2x-2x^{-1}+4=0[/tex]
=> [tex]x^{2}+x^{-2}-4x-4x^{-1}+6=0[/tex]
=> [tex]x^{2}+x^{-2}-4(x+x^{-1})=-6[/tex]
=> [tex]x^{2}+x^{-2}-8=-6[/tex]
=> [tex]x^{2}+x^{-2}=2[/tex]
16. lim x→ 1 (∛(x^2 )- 2∛(x+1))/〖(x-1)〗^2
Matematika Kelas XI SMA
Bab Limit
17. 2∣x−1∣≤∣x+2∣[tex]2∣x−1∣≤∣x+2∣[/tex]2∣x−1∣≤∣x+2∣
Jawaban:
428#@72:$@9264388#@kamu itu sanga tidak pintar kon
18. { ((x^2/3)+(x^1/2))*((x^1/3)-(1/(x^1/3))) } / { ((x^1/2)+1/(x^1/2))*(x-(x^1/3)) } =...
[tex]( x^{ \frac{3}{2} } + x^{ \frac{1}{2} }) ( x^{ \frac{1}{3} } - x^{ -\frac{1}{3} } )[/tex]
[tex]( x^{ \frac{1}{2} } + x^{ -\frac{1}{2} }) ( x - x^{ \frac{1}{3} } )[/tex]
[tex] x^{ \frac{1}{2} } (x + 1) x^{- \frac{1}{3} } ( x^{ \frac{2}{3} } + 1) [/tex]
[tex] x^{ -\frac{1}{2} }(x + 1) x^{ \frac{1}{3}}(x^{ \frac{2}{3} } - 1) [/tex]
dicoret coret
=
[tex] \sqrt[3]{x} [/tex]
19. 1) 1 1/2 x 1 = 2) 1/2 x 1 = 3) 1 1/2 x 2 = 4) 1/2 x 2 =
1. 1 1/2 × 1 = 3/2 × 1 = 3/2 = 1 1/2
2. 1/2 x 1 = 1/2
3. 1 1/2 x 2 = 3/2 × 2 = 6/2 = 3
4. 1/2 x 2 = 2/2 = 1
Semoga Membantu
Maaf Klo Salah
20. Jika cotan 54° = 1/x, maka cosec 9° =… a. x - 1 / x + 1 b. x + 1 / x - 1 c. √2(x^2 + 1) / x - 1 d. √2(x^2 + 1) / x + 1 e. x - 1 / √2(x^2 + 1)
cosec 9° =…
cotan 54° = 1/x
tan 54° = x
cosec 9° = √2(x² + 1) / x - 1
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