Solve the inequality 7x≥49
1. Solve the inequality 7x≥49
Jawaban:
x = {7 , 8 , 9 , 10...}
Penjelasan dengan langkah-langkah:
= 7x ≥ 49
= 7x : 7 ≥ 49 : 7
= x ≥ 7
x = {7 , 8 , 9 , 10 , 11 12....}
2. solve the inequality. 5x - 3 > 9
[tex]5x - 3 > 9 \\ 5x > 9 + 3 \\ 5x > 12 \\ x > \frac{12}{5} \\ x = \frac{12}{5} \: atau \: 2 \: \frac{2}{5} \: atau \: 2.4[/tex]
3. solve the inequality k^2-4k+3<0
Jawaban:
1<k<3
(1,3)
semoga bermanfaat
4. Solve the absolute value inequality. Express the answer using interval notation.6 – |2x + 3| < 5
Jawab:
Penjelasan dengan langkah-langkah:
jika |a| < b maka - b <x < b
soal
6 – |2x + 3| < 5
- |2x + 3| < 5 - 6
- |2x + 3| < - 1
|2x + 3 > 1
2x + 3 > 1 atau 2x + 3 < - 1
2x > 2 atau 2x < - 4
x > 1 atau x < - 2
HP x = { x < -2 atau x > 1 }
5. how can i solve this?
sec 72×1,25= tangga
3.2360679775×1,25=tangga
4.0450849719=tangga
tangga×sin72-1,15=tangga
2.6971044215
6. Can you solve this? If
jawabannya adalah (a) yg artinya sebuah ,seekor,tergantung bendanya.
maaf kalo salah
7. Solve this question
9. long of the ribbon = 3 meter
1 pcs ribbon = 3/5 m
The total pieces of ribbon obtained are
= 3 meter : 3/5 m
= 3 meter x 5/3 meter
= 5 pcs
10.
student's that mrs tanri have is
= 24 : 3/4
= 24 x 4/3
= 32 students
8. solve the inequality [tex] 2^{1-x}- 2^{x+2} \ \textless \ 7 [/tex] tolong dong
[tex] 2^{1-x} - 2^{x+2}\ \textless \ 7 \\ 2 ^{1}.2 ^{-x} - 2^{x}. 2^{2} \ \textless \ 7[/tex]
*Kalikan seluruhnya dengan [tex]2 ^{x} [/tex]
[tex]2-2 ^{2x}.4\ \textless \ 2^{x} .7 [/tex]
*Misalkan [tex]2 ^{x}=a [/tex]
[tex]2-a^{2} .4\ \textless \ a.7 \\ 2-4a ^{2} -7a\ \textless \ 0 \\ 4a ^{2}+7a-2\ \textgreater \ 0 \\ (4a-1)(a+2)\ \textgreater \ 0 [/tex]
4a - 1 > 0 atau a + 2 > 0
4a > 1 atau a > -2
a > [tex] \frac{1}{4} [/tex] atau a > -2
*a > -2 tidak dapat dikerjakan, karena hasil logaritma dari bilangan negatif memiliki hasil yang tidak dapat didefinisikan.
[tex]2^{x}\ \textgreater \ \frac{1}{4} [/tex]
[tex]x\ \textgreater \ log_{2} (\frac{1}{4}) [/tex]
[tex]x \ \textgreater \ -2[/tex]
9. How to solve this question
Jawaban:
gatauh donk
cari di google aja deh
10. Please Solve This! Thanks
[tex] \sqrt{ \frac{x - 1}{x + 2} } < \sqrt{ \frac{x + 3}{x + 1} } \: kuadrat kan \\ \frac{x - 1}{x + 2} < \frac{x + 3}{x + 1} \\ \frac{x - 1}{x + 2} - \frac{x + 3}{x + 1} < 0 \\ \frac{ {x}^{2} - 1 - ( {x}^{2} + 5x + 6)}{(x + 2)(x + 1)} < 0 \\ \frac{ - 5x - 7}{(x + 2)(x + 1)} < 0 \\ x = \frac{ - 7}{5} \\ x = - 2 \\ x = - 1 \\ - 2 < x < \frac{ - 7}{5} atau \: x > - 1[/tex] lanjut ada di foto
11. solve this simultaneous equation!
Jawab:
3x + 4y = 14
5x + 2y = 21
3x + 4y = 14
10x + 4y = 42
---------------------- -
-7x = -28
x = 4
3 . 4 + 4y = 14
12 + 4y = 14
4y = 2
y = 1/2
12. anyone can solve this?
Jawab:
Penjelasan dengan langkah-langkah:
Karena kau beri soal kertas ku jawab pula dengan kertas.
13. can you solve this?
Jawaban:
Penjelasan dengan foto terlampir.
14. two times a number plus 5 less then 25.solve the inequality!thx for the help
2x + 5 < 25 2x < 20 x < 10 semoga membantu kak
15. Can you solve this?
jawabannya adalah (a) yg artinya sebuah
maaf kalo salah
16. please solve this puzzle!
(2+3).2=10
(8+4).8=96
(7+2).7=63
(6+5).6=66
(9+5).9=126
17. Help me solve this question
berpurat2 rsa otak kuuu..mff yaa
18. someone pls solve this
Penjelasan dengan langkah-langkah:
cari dulu panjang CE
CE = √(CD² + DE²)
CE = √(16² + 12²)
CE = √(256 + 144)
CE = √400
CE = 20 cm
kemudian cari panjang EF
EF = √(CF² - CE²)
EF = √(29² - 20²)
x = √(841 - 400)
x = √441
x = 21 cm
19. Can you solve this?
i am verry sorry i can't help you
20. Please help me solve this
1. cari panjang PS dengan pythagoras ΔPTS
2. cari panjang PR dengan pythagoras ΔPTR
3. Masukan rumus
[tex]cos \alpha = \frac{b^{2} +c^{2} - a^{2}}{2bc} [/tex]
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